We are asked about the fraction of pizza each student
gets, so the relevant numbers here is only 14 students and 7 pizzas. SO the
fraction of pizza each student get is the ratio of the two:
fraction = 7 pizzas / 14 students
fraction = 1 / 2
<span>So each student gets 1/2</span>
Using the determinant method, the cross product is
so the answer is B.
Or you can apply the properties of the cross product. By distributivity, we have
(3i + 8j - 6k) x (-4i - 2j - 3k)
= -12(i x i) - 32(j x i) + 24(k x i) - 6(i x j) - 16(j x j) + 12(k x j) - 9(i x k) - 24(j x k) + 18(k x k)
Now recall that
- (i x i) = (j x j) = (k x k) = 0 (the zero vector)
- (i x j) = k
- (j x k) = i
- (k x i) = j
- (a x b) = -(b x a) for any two vectors a and b
Putting these rules together, we get
(3i + 8j - 6k) x (-4i - 2j - 3k)
= -32(-k) + 24j - 6k + 12(-i) - 9(-j) - 24i
= (-12 - 24)i + (24 + 9)j + (32 - 6)k
= -36i + 33j + 26k
First we write the statement step by step to find the correct equation.
We have then:
x - y
subtracted from 0
(0) - (x-y)
Resolving:
(0) - (x-y) = - x + y
You should notice that different signs are subtracted and equal signs are added.
Answer:
A) -x + y
Answer:
ANSWER
n < - 3 \: or \: n > - 2n<−3orn>−2
EXPLANATION
The given inequality is,
|2n + 5| \: > \: 1∣2n+5∣>1
By the definition of absolute value,
- (2n + 5) \: > \: 1 \: or \: (2n + 5) \: > \: 1−(2n+5)>1or(2n+5)>1
We divide through by negative 1, in the first part of the inequality and reverse the sign to get,
2n + 5 \: < \: - 1 \: or \: (2n + 5) \: > \: 12n+5<−1or(2n+5)>1
We simplify now to get,
2n \: < \: - 1 - 5 \: or \: 2n \: > \: 1 - 52n<−1−5or2n>1−5
2n \: < \: - 6 \: or \: 2n \: > \: - 42n<−6or2n>−4
Divide through by 2 to obtain,
n \: < \: - 3 \: or \: n \: > \: - 2n<−3orn>−2
Answer:
decimal=0.625
percent=62.5%
Step-by-step explanation:
mark brainliest pls and hope this helps u
