Answer: x=1 y=-3
just look where the line touches mane
First equate 4x+7y=3x,
we get, x+7y=0 ---->equ 1
Now equate 3x=y-2, we get 3x-y=-2 ----->equ2
solve equ 1,2,
We get x= -7/11, y=1/11
We have a three unknown, 4 equation homogeneous system. These always have at least (0,0,0) as a solution. Let's write the equations, one column at a time.
1a + 0b + 0c = 0
-1a + 1b +0c = 0
0a - 1b + c = 0
0a + 0b + -1 c = 0
We could do row reduction but these are easy enough not to bother.
Equation 1 says
a = 0
Equation 4 says
c = 0
Substituting in the two remaining,
-1(0) + 1b + 0c = 0
b = 0
0(0) - 1b + 0 = 0
b = 0
The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)
Step-by-step explanation:
cos 0=5/13. B/H
p=√h2 - b2
= √13 square -5 square
=√169 -25
=√144
=12 Ans
Tan0=p/b =12/5. , sin0=p/h =12/13,. sec0= h/b =13/5 ,. Co sec0 =h/p =13/12 , cot0 =b/p=5/12
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