Answer:
1.49
Step-by-step explanation:
In order to find the slope of the tangent line to a given equation, and in a given point, we need to:
1. Find the first derivative of the given function.
2. Evaluate the first derivative function in the given point.
1. Let's find the first derivative of the given function:
The original function is 
But remeber that the derivative of 
is
so, 
2. Let's evaluate the first derivative function in the given point
The given point is (0.4,1.49) so:
Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.
<span>The missing angle measure in triangle ABC is 55°.
The measure of angle BAC in triangle ABC is equal to the measure of angle
EDF in triangle DEF.
The measure of angle ABC in triangle ABC is equal to the measure of </span><span>angle EFD in triangle DEF.
Triangles ABC and DEF are similar by the angle-angle criterion.
True </span>
Morgan earns more money per hour on saturday bc 63/6 = 10.5 and that’s more than 9.5 so
Answer: (Mayadc821 wrote this anwser check theyre account for more)
Since you know the x and y values, you just have to plug these into the linear slope-intercept equation:
y = mx + b
-10 = m(1) + b
m + b = -10
b = -10 - m
Now that we have a value for b, we can plug this into the other equation:
8 = m(-8) + b
8 = -8m + (-10 - m)
8 = -9m -10
18 = -9m
m = -2
Now that we know what m is equal to, we can plug this into our first equation to get an answer for b:
b = -10 - m
b = -10 -(-2)
b = -10 + 2
b = -8
Our final equation is y = -2x - 8
