<span>As mentioned, the isomerization of cyclopropane to propylene is a first-order process with a half-life of 19 min at 500°c. A first-order reaction kinetic rates means that the rate is constant throughout the reaction.
Thus, the time it takes for the partial pressure of cyclopropane to decrease from 1 atm to 0.125 atm at 500°c is </span><span>57 minutes.</span>
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Empirical formula =?
Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Mass of Hydrogen (H) =?
Mass of H = mass of compound – mass of C
Mass of H = 6.32 – 5.41
Mass of H = 0.91 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of C = 5.41 g
Mass of H = 0.91 g
Divide by their molar mass
C = 5.41 / 12 = 0.451
H = 0.91 / 1 = 0.91
Divide by the smallest
C = 0.451 / 0.451 = 1
H = 0.91 / 0.451 = 2
Thus, the empirical formula for the compound is CH₂
The simplest ratio of the constituent elements
The Zeroth Law of Thermodynamics<span> states that if two bodies are each in thermal equilibrium with some third body, then they are also in equilibrium with each other. Credit: Tim Sharp</span>
Answer:
The balanced equation is.
CH₄ + 2O₂ → CO₂ + 2H₂O
Explanation:
CH₄ + O₂ --> CO₂ + H₂O
You have 4 H in reactant side. In order to balance the H, you add 2 in water, in product side.
Now, you unbalanced the O, because you have 2 O from CO₂ and 2 O from water. As you have 4 O in total, you add a 2 in the O₂ in the reactant side. C is balanced because you have 1 C on each side