I don't get the problem to 6j-3 for j=4
1 answer:
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Answer:
100+20π
Step-by-step explanation:
Find the diagram attached.
Perimeter of a square =4L
L is the side length of a square
From the diagram;
L = 10
Perimeter of a square = 4(10) = 40
Perimeter of 3 squares = 3(40) = 120
2 semi circle = a circle
Perimeter of a circle= 2πr
radius of the Circle = length of a side of the square.
Area of the circle = 2π(10)= 20π
Perimeter of the shape = Perimeter of the two semicircle + area of the 4squares = 100+20π
Answer:
Linear function with rate of change/growth = 2.5, which agrees with the fourth statement listed in the answers options.
Step-by-step explanation:
Notice that both columns of reported x and y values are increasing.
Then examine how the given x-values increase:
-2, 2, 6, 10, 14 (in steps of 4 units)
and how their corresponding y-values increase:
-2, 8, 18, 28, 38 (in steps of 10 units)
therefore, if we do the rate of change for any pair and
, we get the following constant rate of change:
Given that this relationship is valid for any pair of (x,y) values. we conclude that the rate of increase is constant, and therefore we are in the presence of a linear function, whose rate of change is 2.5