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Hatshy [7]
3 years ago
11

Whats the original price of a pair of shoes in the sale price is $27 after a 25% discount

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0

the original price would have been $36

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From the table below create an equation.
Bond [772]

Answer:

Step-by-step explanation:

2,4 ,10,12,19,36.5,40

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What is 10x10? I really need some help please and thank you.
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0 points<br> 6a – 14a2 + 8a + 1 by a - 2
Mekhanik [1.2K]

Answer:

-14a -14- 27/a-2 hope this helps

Step-by-step explanation:

6 0
3 years ago
If 18√8 - 8 √18 = √n, what is n?
Yuliya22 [10]

Answer:

n=288

Step-by-step explanation:

Rewrite the equation as  

√

n

=

18

√

8

−

8

√

18

.

√

n

=

18

√

8

−

8

√

18

To remove the radical on the left side of the equation, square both sides of the equation.

√n

2

=

(

18

√

8

−

8

√

18

)

2

Simplify each side of the equation.  

Use  

n

√

a

x

=

a

x

n

to rewrite  

√

n  as  n

1

2

.

(

n

1

2

)

2

=

(

18

√

8

−

8

√

18

)

2

Simplify  

(

n

1

2

)

2

.  

Multiply the exponents in  

(

n

1

2

)

2

.  

Apply the power rule and multiply exponents,  

(

a

m)n

=

a

m

n

.

n

1

2

⋅

2

=

(

18

√

8

−

8

√

18

)

2

Cancel the common factor of  2  

Cancel the common factor.

n

1

2

⋅

2

=

(

18

√

8

−

8

√

18

)

2

Rewrite the expression.

n

1

=

(

18

√

8

−

8

√

18

)

2

Simplify.

n

=

(

18

√

8

−

8

√

18

)

2

Simplify  

(

18

√

8

−

8

√

18

)

2

Simplify each term.

Rewrite  

8  as  2

2

⋅

2

.  

Factor  

4  out of  8  

n

=

(

18

√

4

(

2

)

−

8

√

18

)

2

Rewrite  

4  as  2

2  

n

=

(

18√

2

2

2

−

8

√

18

)

2

Pull terms out from under the radical.

n

=

(

18

(

2

√

2

)

−

8

√

18

)

2

Multiply  

2  by  18  

n

=

(

36

√

2

−

8

√

18

)

2

Rewrite  

18

as  

3

2

⋅

2

.

Factor  

9

out of  

18

.

n

=

(

36

√

2

−

8

√

9

(

2

)

)

2

Rewrite  

9

as  

3

2

.

n

=

(

36

√

2

−

8

√

3

2

⋅

2

)

2

Pull terms out from under the radical.

n

=

(

36

√

2

−

8

(

3

√

2

)

)

2

Multiply  

3

by  

−

8

.

n

=

(

36

√

2

−

24

√

2

)

2

Simplify terms.

Subtract  

24

√

2

from  

36

√

2

.

n

=

(

12

√

2

)

2

Simplify the expression.

Apply the product rule to  

12

√

2

.

n

=

12

2

√

2

2

Raise  

12

to the power of  

2

.

n

=

144

√

2

2

Rewrite  

√

2

2

as  

2

.

Use  

n

√

a

x

=

a

x

n

to rewrite  

√

2

as  

2

1

2

.

n

=

144

(

2

1

2

)

2

Apply the power rule and multiply exponents,  

(

a

m

)

n

=

a

m

n

.

n

=

144

⋅

2

1

2

⋅

2

Combine  

1

2

and  

2

.

n

=

144

⋅

2

2

2

Cancel the common factor of  

2

.

Cancel the common factor.

n

=

144

⋅

2

2

2

Rewrite the expression.

n

=

144

⋅

2

1

Evaluate the exponent.

n

=

144

⋅

2

Multiply  

144

by  

2

.

n

=

288

5 0
3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
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