Answer:
3 meters
Step-by-step explanation:
We assume the storage room is a rectangle, like most rooms, no indication it is otherwise.
We know it's a rectangle and not a square because it is longer than wide.
We have the perimeter measurement (16 meters).
So, we can make the following equation:
2x + 2y = 16
x being the width of the room, y being it's length. A perimeter is the sum of all sides.
We also know the room is 2 meters longer than wide... so:
y = x + 2
If we replace y in the first equation by its value relative to x, we get:
2x + 2(x + 2) = 16 which becomes
2x + 2x + 4 = 16
4x =12
thus x = 3
Width: 3 meters
Length: 5 meters.
Confirms the 16 meters perimeter.
Answer:
x = 4 or x = -3/2
Step-by-step explanation:
To simplify and solve this, let's use the quadratic formula.
So the format of a quadratic equation is supposed look like this:
Let's find a, b, c:
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
Now let's solve the equation.
Let's solve your equation step-by-step.
2x^2−5x−12=0
For this equation: a=2, b=-5, c=-12
2x^2+−5x+−12=0
Step 1: Use quadratic formula with a=2, b=-5, c=-12.
or 
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<u>Answer:</u>
x = 4 or x = -3/2
The difference between the masses is
4.55·10¹³ kg -1.78·10¹² kg
= 4.55·10¹³ kg - 0.178·10¹³ kg
= (4.55 -0.178)·10¹³ kg
= 4.372·10¹³ kg
Rounded to the appropriate precision, the mass of the Antarctic iceberg exceeds that of the Rock of Gibraltar by ...
4.37·10¹³ kg
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
