To solve this problem, we can use the tan function to find
for the distances covered.
tan θ = o / a
Where,
θ = angle = 90° - angle of depression
o = side opposite to the angle = distance of boat from
lighthouse
a = side adjacent to the angle = height of lighthouse = 200
ft
When the angle of depression is 16°18', the initial distance
from the lighthouse is:
o = 200 tan (90° - 16°18')
o = 683.95 ft
When the angle of depression is 48°51', the final distance
from the lighthouse is:
o = 200 tan (90° - 48°51')
o = 174.78 ft
Therefore the total distance the boat travelled is:
d = 683.95 ft - 174.78 ft
<span>d = 509.17
ft</span>
You can solve this by cross multiplying. 20 ounces/$7=x ounces/$17. multiple $17 by 20 ounces and $7 by x ounces. (17x20=7x). 17x20=340, so 340=7x. Divide both sides by 7, and you will get x equals about 48.6.
Answer:
A
Step-by-step explanation:
3y (-5)(y+2)
3y(-5y-10)
3y-5y-10
-2y-10
-2y-10
Answer:
![f(x)=\sqrt[3]{x} \\a=5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%5C%5Ca%3D5)
Step-by-step explanation:
