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kipiarov [429]
3 years ago
6

How do I do this. I need help fast

Mathematics
2 answers:
zvonat [6]3 years ago
7 0
It is about 70 yards
Wewaii [24]3 years ago
6 0
It'll be 70 yards...
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MORE EASY 7TH GRADE MATH<br><br> X/2=95 <br><br><br> THANK YOU
SIZIF [17.4K]

Answer:

X/2=95

X= 95*2

X=190

Step-by-step explanation:

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3 years ago
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some friends need 100 bows for a project Sara brings 12 bows Angela brings 50 bows and Nora brings 34 bows how many more bows do
Irina-Kira [14]
They need 4 more because 12+50+34=96 96-100 is 4 hope this helps ya
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3 years ago
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What is the range of the function represented by these ordered pairs?
Finger [1]

Answer:

Choice 2

Step-by-step explanation:

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3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
What are the similarities between a square and a trapezoid
Blababa [14]
A square  is a square  a trapezoid is a lot weirder <span />
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3 years ago
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