Answer:
2980
Step-by-step explanation:
2.98*10^3 = 2980
The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;
Which gives;
6•x² - 106•x + 315 = 0
Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
brainly.com/question/13058734
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In order to answer this one, it's really really really really helpful if you know what the law of cosines says. In fact it's absolutely necessary.
The law of cosines says if you know two sides of a triangle and the angle between them then you can use that information to find the length of the third side.
In the picture you know the lengths of two sides and you know the angle between them. So you can use the law of cosines to find the length of the third sidethat. That's side AC.
Answer:
The dimensions are 6 by 5 feet.
Length = 6 feet.
Width = 5 feet.
Step-by-step explanation:
Let the length = L
Let the width = W
Perimeter of a rectangle = 2L + 2W
Translating the word problem into an algebraic equation, we have;
L = 2W - 4 ........equation 1
22 = 2L + 2W .......equation 2
Substituting the value of "L" into equation 2, we have;
22 = 2(2W - 4) + 2W
22 = 4W - 8 + 2W
22 + 8 = 6W
30 = 6W
W = 30/6
Width, W = 5 feet.
To find the length, L
Substituting the value of "W" into equation 1, we have;
L = 2W - 4
L = 2(5) - 4
L = 10-4
Length, L =6 feet
Therefore, the dimensions of the garden are 6 by 5 feet.
First Question:
Number of trapezoids - 6
Perimeter - 72
3 + 3 + 3 + 6 = <u>15</u>
3 + 3 + 3 + 3 + 6 + 6 = <u>24</u>
3 + 3 + 6 + 3 + 3 + 6 + 3 + 6 = <u>33</u>
15 + 24 + 33 = <u>72</u>
Second Question:
Number of cubes - 6
Surface area - 24 (probably 480 since it said <em>area</em>)
first cube - 6 ones
second cube - 8 ones
Third cube - 10 ones
you could do 6 + 8 + 10 = 24 or add up all the ones (1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1) and you will still get 24
(It said <em>area</em>, and area means to multiply so maybe its 6 x 8 x 10 = 480 and not 6 + 8 + 10)
Anyways have a good day/night :) I might be wrong, but I hope I helped at least a little
