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NeTakaya
3 years ago
8

The graph shows the price, in dollars, of different numbers of sweet breads at Alan's store. The table shows the price, in dolla

rs, of different numbers of shortcakes at the same store.
Shortcake

Number
of Shortcake Price of Shortcake
(dollars)
5 45
10 90
15 135
20 180


How many dollars more is the price of a shortcake than the price of a sweet bread at David's store?

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0
Each of the sweetbread costs $4 whilst each shortcake cost $9. So, the price of a shortcake will cost $5 more. :)  
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P(a)=0.50 p(b)=0.30 and p(a and b)=0.15 what is p(a or b)
Softa [21]

Answer:

Option C is correct

P(A or B) = 0.65

Step-by-step explanation:

<u>Given: </u>

P(A) =0.5

P(B)=0.30

P(A and B) =0.15

( The probability of the happening of both independent events will be there product) P( A and B ) =P(A).P(B)

<u>Solution:</u>

To find the probability  of the Happening of event A either event B  we will use the following formula

P(A or B) = P(A) + P(B)-P(A and B)

                  = 0.5 + 0.3 - 0.15

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6 0
3 years ago
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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

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\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

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4 0
3 years ago
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IrinaVladis [17]
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100% of hives = 6 × 100 = 600

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Step-by-step explanation:

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