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Nonamiya [84]
4 years ago
15

What are thesolutions to the quadratic equation 0=−32−4+5?

Mathematics
1 answer:
const2013 [10]4 years ago
5 0

Answer:

-31

Step-by-step explanation:

0 equal nothing so you will do -32-4+5 to get your answer

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Please help solve this question been stuck for a while​
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Answer:

7.7

Step-by-step explanation:

To find the intersection points of the line and the circle we have to set up a system with their equations and solve. The system would look like this:

\left \{ {{x=1              } \atop {x^2+y^2=16}} \right.

To solve, substitute 1 for x in the second equation to get:

1^2+y^2=16

Solving, we get:

y=\sqrt{15}, y=-\sqrt{15}

Therefore, the two points of intersection are (1,\sqrt{15} ) and (1,-\sqrt{15}). The distance between these two points (the length of the chord in the circle) is 2\sqrt{15} which is 7.745966692414... which is 7.7 rounded to the nearest tenth.

Hope this helps :)

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Answer:

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