Given :
An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.
To Find :
The airplane’s angle of decent.
Solution :
Height of plane, h = 2600 m.
Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.
Let, angle of depression is Ф.
So,

Therefore, the angle of decent is 87.34°.
Hence, this is the required solution.
Answer
Step 1: Add -x^2 to both sides.
x2+c+8x+−x2=0+−x2
c+8x=−x2
Step 2: Add -8x to both sides.
c+8x+−8x=−x2+−8x
c=−x2−8x
Answer:
c=−x2−8x
I hope is is the answer you are looking for

insert x = -2



option D. 3/4 will be the correct answer.
26 is probably the answer