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meriva
3 years ago
7

Please need help asap!!

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0
Option(4.)is the answer to ur question
Angle DXY
Hope This helps u...!!!
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if, while training for a marathon, you run 88 miles in 2 4/5 months, how many miles did you run each month?
nlexa [21]
Hi,

Let's solve this problem mathematically.

2\frac{4}{5} = 2.8
88 \div 2.8 = 31.42

Result = 31.42
Hope this helps!
r3t40
8 0
3 years ago
Distance run by each member
saw5 [17]

Answer:

The median is the middle term in the arranged data set. ... The median class interval is the corresponding class where the median value falls.

Step-by-step explanation:

The median is the middle term in the arranged data set. ... The median class interval is the corresponding class where the median value falls.

8 0
3 years ago
What are the Ratio 4:5 and 8:10?
miv72 [106K]

Answer:

4/5 = 80% and 8/10 = 80%

Step-by-step explanation:

3 0
3 years ago
Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation
Olenka [21]

Answer:

y = \frac{49}{3}

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 7 when x = 3

k = \frac{y}{x} = \frac{7}{3}, thus

y = \frac{7}{3} x ← equation of variation

When x = 7, then

y = \frac{7}{3} × 7 = \frac{49}{3}

8 0
3 years ago
Find the perimeter of the quadrilateral.
levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0
3 years ago
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