Answer: Option D

Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation

To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:

Where 
In this case the equation is: 
Then

So:


Answer:
About 13.32 Pounds
Step-by-step explanation:
First. take the total weight of the three boxes and divide it by the number of boxes.
10/3 = 3.33 and so on
Now we know each box ways 3.33 pounds.
Now multiply 4 boxes by 3.33 pounds.
4 x 3.33 = 13.32
So the answer should be about 13.32 pounds.
4|x - 1| - 7 = -3 |add 7 to both sides
4|x - 1| = 4 |divide both sides by 4
|x - 1| = 1 ⇔ x - 1 = 1 or x - 1 = -1 |add 1 to both sides
x = 2 or x = 0
Answer: B.