Answer:
0.13% of customers spend more than 46 minutes
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What percentage of customers spend more than 46 minutes?
This is 1 subtracted by the pvalue of Z when X = 46. So
has a pvalue of 0.9987
1 - 0.9987 = 0.0013
0.13% of customers spend more than 46 minutes
Answer:it’s y+3=6x
Step-by-step explanation:
Answer:
• discriminant: 73
• # of real solutions: 2
Step-by-step explanation:
Comparing the equation ...
2x^2 -9x +1 = 0
to the generic form ...
ax^2 +bx +c = 0
we find the coefficient values to be ...
a = 2; b = -9; c = 1
That makes the value of the discriminant, (b^2 -4ac), be ...
(-9)^2 -4(2)(1) = 81 -8 = 73
Since the discriminant is positive, the number of real solutions is 2.
Answer:
8^2
Step-by-step explanation:
We know that a^b / a^c = a^(b-c)
8^9 / 8^7 = 8^(9-7) = 8^2
Company A:
$200 + $2.99(30ft * 50ft) = $4,685
Company B:
30ft x 50 ft = 166.6667 sq yd.
$500 + $19.99(166.6667sq yd) = $3831.667
Company B is the better deal