Answer:
a. 4
b. 1/4
c. 16
d. 1/9
e. 4/9
f. 9/16
Step-by-step explanation:
The ratio of the areas is the square of the ratio of the lengths of the sides.
a. Triangles G and F
Select a side in triangle G and the corresponding side in triangle F:
side in F: 10
corresponding side in G: 5
ratio of lengths of F to G = 10/5 = 2
ratio of areas of G to F: (2)^2 = 4
b. Triangles G and B
Select a side in triangle G and the corresponding side in triangle B:
side in G: 5
corresponding side in B: 5/2
ratio of lengths of B to G = (5/2)/5 = 1/2
ratio of areas of B to G: (1/2)^2 = 1/4
c. Triangles B and F
Select a side in triangle B and the corresponding side in triangle F:
side in B: 5/2
corresponding side in F: 10
ratio of lengths of F to B = 10/(5/2) = 4
ratio of areas of F to B: (4)^2 = 16
Do the same for the other 3 pairs of triangles.
The answers are:
d. 1/9
e. 4/9
f. 9/16
Answer:
GH = (5, -3)
Step-by-step explanation:
The horizontal extent of the vector is 5 squares; the vertical extent is 3 squares. H has a lower y-value than G, so the vertical component is -3.
GH = (5, -3)
Answer:
y = (-1/6)x
Step-by-step explanation:
As we move from (-3, 0.5) to (3, -0.5), x increases by 6 and y decreases by 1.
Hence, the slope of this line is m = rise / run = -1/6.
Starting with the slope-intercept form of the equation of a straight line, we have:
y = mx + b. We substitute 0.5 for y, -3 for x and -1/6 for m, obtaining:
0.5 = (-1/6)(-3) - b, or:
0.5 = 0.5 - b. Then b = 0, and the desired equation is
y = (-1/6)x
Answer:
y = 2x - 3
Step-by-step explanation:
We are asked to find the equation of a straight line
Step 1: find the slope
( 2 , 1) ( 5 , 7)
x_1 = 2
y_1 = 1
x_2 = 5
y_2 = 7
Insert the values into the equation
m = (y_2 - y_1 )/ (x_2 - x _1)
m = (7 - 1 )/ (5 - 2)
m = 6/3
= 2
Step 2: substitute m into the equation
y = mx + c
y = 2x + c
Step 3 : sub any of the two points given into the equation
Let's use ( 2, 1)
x = 2
y = 1
y = 2x + c.
1 = 2(2) + c
1 = 4 + c
c = 1 - 4
c = -3
Step 4: sub c into the equation
y = 2x + c
y = 2x - 3
<em>x equals 22</em>
<h2>
Explanation:</h2>
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The Segment Postulate states the following:
<em>Given two end points A and B, a third point C lines on the segment AB if and only if the distances between the points satisfy the equation:</em>

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From the figure:

Our goal is to find x:

<h2>Learn more:</h2>
Dilation: brainly.com/question/2501119
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