f(x)=2x^3+2x^2-4x
The zeros of polynomial functions
2x^3 + 2x^2 - 4x = 0
2x(x^2 + x - 2) = 0
2x(x - 1)(x + 2) = 0
2x = 0; x = 0
x - 1 = 0; x = 1
x + 2 = 0; x = -2
Answer
x = -2 , 0 , 1
Answer:
3 1/8
Step-by-step explanation:
6 1/4 ÷ 2
~Turn each number into an improper fraction
25/4 ÷ 2/1
~Copy Dot Flip
25/4 * 1/2
~Multiply
25/8 or 3 1/8
Best of Luck!
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
Answer:
y+1=-5(x-1)
Step-by-step explanation:
We need to find the slope intercept form first. So far we have this: y=-5x+b. We could plug in the x value and y value to get this : -1=-5(1)+b. b=4. Now we have the slope intecept form: y=-5x+4, and we could turn it into point slope form.
