An object travels 60 miles in 1/2 hour. How many miles does the object travel in 6 hours
2 answers:
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Answer:
The correct option is;
B. 50 km/h
Step-by-step explanation:
The information given in the question are;
The distance between the two cities = 140 km
The direction of motion of the first car = From A to B (left)
The direction of motion of the second car = From B to A
The time after which both cars meet = 1 hour
The time duration it takes after both cars meet for the second car to reach A = 35 minutes
The total time taken by the second car from city B to city A = The time it takes to meet the first car + The time it takes after meeting the first car to reach city A
∴ The total time taken by the second car from city B to city A = 1 hour + 35 minutes = 60 minutes + 35 minutes = 95 minutes
95 minutes = 95/60 hours = 1⁷/₁₂ hours = 1.58 hours
The speed of the second car = Distance/Time = 140 km/(1.58 hours) ≈ 88.42 km/h
Therefore, let the distance from A of the point the first car meet the second car = x
Therefore, we have;
The distance from B of the point both cars meet = (140 - x) km
Given that both cars meet after one hour, we have;
The distance travelled by the second car coming from city B, after one hour = (140 - x) km = Speed of the second car × 1 hour
88.42 km/h × 1 hour = 88.42 km = (140 - x) km
x = 140 - 88.42 ≈ 51.58 km
The distance from A of the point the first car meet the second car = x = 51.58 km
The speed of car A = (The distance from A of the point the first car meet the second car)/(Time it takes both cars to meet)
∴ The speed of the first car = 51.58 km/(1 hour)
The speed of the first car = 51.58 km/h ≈ 50 km/h (Rounding up to the nearest 10th).
9514 1404 393
Answer:
D
Step-by-step explanation:
Multiplying the inequality by 2 will eliminate the fraction and give you ...
x ≤ 36
The "or equal to" part of the symbol means the end dot will be solid. The "less than" part of the symbol means the graph is shaded to the left of the end dot, which is at x=36. This description matches the graph shown below.
