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Andre45 [30]
3 years ago
13

The system shown below is . x + 3y = 4 3x + 9y = 12

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

Answer:

Consistent and Dependent

Step-by-step explanation:

Just did the question

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Mel is taking her holidays. She receives $2937.50. This includes her normal pay
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8 0
4 years ago
Its really urgent. I need help with the first question.
RUDIKE [14]
This kind of exercise can be real drudgery.  But it's almost all simple arithmetic, so better you than me.  I'll do one of these for you, which will show you how to do the other one.

a).  sin · cot / sec

You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].

Then the problem becomes

         sin · (cos/sin) / (1/cos)  =  cos²

Aw shucks, I might as well also set up 'b)' for you:

b).  cos · csc / tan

You're supposed to know that [ cosecant = 1/sine ]
and  [ tangent = sine/cosine ].

Then the problem becomes

             cos · (1/sin) / (sin/cos)  =  (cos/sin)²

Now simply plug in the given values of cos A and sin A .


And may I compliment you on your nail care !
7 0
3 years ago
If you place the north pole of a magnet near the north pole of another magnet, what do you except to happen
slavikrds [6]
They will repel each other
8 0
3 years ago
Read 2 more answers
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0
2 years ago
Answer this math problem please, brainliest gets 30 pts
-BARSIC- [3]
(3,2)(0,0)
slope = (2-0)/(3-0) = 2/3
b = 0
so
equation
y = 2/3x

answer is C.
y = 2/3x 
4 0
4 years ago
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