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Nady [450]
2 years ago
9

Help!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Stells [14]2 years ago
7 0

your answer is B. I believe im not 100% sure though.

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Sami earns £4.50 per hour. How many hours does he need to work to earn £90?
Citrus2011 [14]

Answer:

20 hours hope this helps :)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone hep me on this
Pavel [41]
5x+4y= $35
x= daisies and y=roses
3x+6y=$39
7 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
What is the length of arc S shown below?<br> The angle in the figure is a central angle in radians.
Taya2010 [7]

Answer:

2

Step-by-step explanation:

Arc length = r × theta

Arc length = 5 × 0.4

= 2

3 0
3 years ago
Use technology to find points and then graph the line y=-5(x-5)+1 following the instructions below.
Svetach [21]

Given:

y=-5(x-5)+1

First, let us find two points from this equation.

We can set values of x and then solve for y.

Let us find the values of y when x = 1, 2, 3, 4, 5

\begin{gathered} y=-5(x-5)+1 \\ y=-5(1-5)+1=21 \\ y=-5(2-5)+1=16 \\ y=-5(3-5)+1=11 \\ y=-5(4-5)+1=6 \\ y=-5(5-5)+1=1 \end{gathered}

We now have a set of points:

(1, 21)

(2, 16)

(3, 11)

(4, 6)

(5, 1)

Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)

The graph would then look like this:

6 0
1 year ago
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