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2 years ago

Can i get some help with geometry

Mathematics

1 answer:

Fudgin [204]2 years ago

8 0

Answer:

first you need to make that into an equation here i think your equation that will help you on that question is 46°+63°=X

Step-by-step explanation:

K-is (4°k+5°y)+(4°k+10°y)=118°

and then what ever you get out of the K's and Y's you will divide that number by 118 and that is the value of K

and this is my opinion

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Which equation describes a line parallel to y= 4x+ 5 through point (-2, 1)?

Keith_Richards [23]

The line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9

<h3>Parallel Equations</h3>

The given equation is:

y = 4x + 5

Compare y = 4x + 5 with the equation y = mx + c

m = 4, c = 5

The equation parallel to y = 4x + 5 will also have a slope, m = 4

The point-slope form of the equation of a line is given as:

y - y₁ = m(x - x₁)

substitute m = 4, x₁ = -2 and y = 1 into the equation above

y - 1 = 4(x - (-2)

y - 1 = 4(x + 2)

y - 1 = 4x + 8

y = 4x + 8 + 1

y = 4x + 9

Therefore the line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9

Learn more on equation of a line here: brainly.com/question/13763238

7 0

2 years ago

Read 2 more answers

Write 10 x 10 x 10 x 10 x 10 x 10 with an exponent. Explain how you decided what exponent to write

valentina_108 [34]

10x10x10x10x10x10=1000000

${10}^{6}$

means 10x10x10x10x10x10

as it's basically saying 10 is multiplied by itself 6 times which gives you 1000000

5 0

3 years ago

Read 2 more answers

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

If y varies inversely as x and y=32 when x=3, find x when y=15

deff fn [24]

Y=kx, k is not equal to 0
when y=32,x=3, 32=3k
k=32/3
so y=32/3*x
when y=15, 15=32/3*x
x=45/32

5 0

3 years ago

Please help!!!

marusya05 [52]

Answer:

the answer is B.FALSE

Step-by-step explanation:

hope it helps

5 0

2 years ago

Can i get some help with geometry​

Can i get some help with geometry