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Goryan [66]
4 years ago
15

The probability that a random variable is greater than or equal to z standard deviations from the mean in a standard normal dist

ribution is p%. What can be said with certainty about the probability that the random variable is less than or equal to –z standard deviations from the mean?
The probability is less than p%.
The probability is equal to p%.
The probability is greater than p%.
The probability is not equal to p%.
Mathematics
2 answers:
lawyer [7]4 years ago
4 0
The 2nd one ..........
trasher [3.6K]4 years ago
4 0

Answer:

2. The probability is equal to p%.

Step-by-step explanation:

We have been given that the probability that a random variable is greater than or equal to z standard deviations from the mean in a standard normal distribution is p%. We are asked to choose the correct statement about the probability that the random variable is less than or equal to –z standard deviations from the mean.

We know that normal distribution curve is symmetric about mean. The z-score of data point shows that the data point is how may standard deviation above or below mean.

A positive z-score means that a data points is that many standard deviation above mean. So positive z will be above mean.

The probability that a variable is greater than or equal to z is given by p%. This probability (p%) represents the distance from z to the right end of the curve.

A negative z-score means that a data points is that many standard deviation below mean. So negative z-score (-z) will be below the mean. The probability that a variable is less than or equal to -z is the distance from -z to the left end of the curve.  

Since a normal distribution curve is symmetric about the mean, therefore, the probability that a variable is less than or equal to -z will be equal to probability that a variable is greater than or equal to z.

Since probability that a variable is greater than or equal to z is given by p%, therefore, the probability that a variable is less than or equal to -z will be p% and 2nd option is the correct choice.

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Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
4 years ago
I’ll give you brainliest for the first person with an answer
raketka [301]

Answer:

1296mm^2

Step-by-step explanation:

Surface Area of the Rectangular Prism to the left on top of the box:

Area of square = lw, 9mm * 9mm = 81mm, then multiply by 2 because 2 of the squares are a part of the surface, giving <u>162mm^2</u>

Area of a rectangle =lw, 9mm * 9mm = 81mm, then multiply by 2 again, because 2 rectangles are a part of the surface, giving <u>162mm^2</u>

So, the total surface area of the rectangular prism to the left on top, is 324mm^2

Surface Area of the Triangular Prism:

Area of a triangle: 1/2bh, and our base length would be 12, because we have to subtract 9 from 21 since the base length of the triangle isn't stated. Anyways, A = 1/2bh, so A = 1/2(12)(9) = 54mm^2, but multiply by two, so we get <u>108mm^2</u>.

Area of the rectangle: lw, so 15mm * 9mm = <u>135mm^2</u>

So, the total surface area of the triangular prism is 243mm^2

Surface Area of the Rectangular Prism at the bottom:

Area of the long rectangles in front = lw, 21mm * 9mm = 189mm^2, multiply by 2, <u>378mm^2</u>

Area of the rectangles to the side = lw, 9mm * 9mm = 81mm^2, multiply by 2, <u>162mm^2 </u>

Area of the rectangle at the very bottom = lw, 21mm * 9mm = <u>189mm^2</u>

So, the total surface area of the rectangular prism at the bottom is 729mm^2

Add all the total surface areas of each shape to get the total surface area of the figure:

324mm^2 + 243mm^2 + 729mm^2 = 1296mm^2

The surface area of the figure above is 1296mm^2

<u />

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Answer:

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