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kotykmax [81]
3 years ago
10

At a children's concert there were 80 boys. There were 1 1/2 times the number of girls as boys. What percentage of the total num

ber of children at the concert were girl?​
Mathematics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

60% are girls

Step-by-step explanation:

80 x 1.5 = 120 which is the amount of girls

120 out of 200 is 12/20 or 3.5 which is 60%

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There were 178 old cars at the junkyard. Then a truck brought in some more cars. Now there are a total of 236 cars in the junkya
crimeas [40]

Answer:

<u>The correct answer is 58 cars.</u>

Step-by-step explanation:

Cars in the junkyard before the truck arrived with some = 178

Cars after the truck brought into the junkyard some more= 236

Cars brought in by the truck = 236 - 178

Cars brought into the junkyard by the truck = 58

<u>The number of cars brought by the truck is 58 cars.</u>

5 0
3 years ago
Please help solve this question with steps
Orlov [11]
39x^3 = 13*3*x*x*x

-6x^2 = 2*3*x*x*-1

-3x    = 3*x*-1

so in all these factorizations, 3*x is common. so 3x is the common factor.

by seperating the common factor,

3x(13x^2 - 2x-1)

will be the factorization.


   xy + 5x - 5y - 25

=x (y+5) -5 (y+5)
=(x-5) (y+5)

hope I helped ya!!!
8 0
3 years ago
What is the area of this figure?​
lesantik [10]

Answer:

\Huge\boxed {A =859ft^{2} }

Step-by-step explanation:

Hello There!

To solve for the area of this figure we need to split the figure into 3 different parts:

A rectangle with a length of 9 ft and a width of 7 ft

a rectangle with a width of 9ft + 7ft and a length of 25 ft

a rectangle with a width of 18 ft and a length of 22 ft

To find the area of a rectangle we use the formula

A=w*l where w = width and l = length

for the first one we plug in the values

A = 9 * 7

9 * 7 = 63 so the area of the smallest rectangle  is 63ft²

Now lets find the area of the larger rectangle

The dimensions are l = 25 ft and w = 9 + 7 (16 ft)

Now we can plug in the values into the area formula

A = 16 * 25

16*25=400 so the area of the larger rectangle is 400 ft²

Now lets find the area of the last rectangle

The dimensions are l = 22 ft and w = 18 ft

now lets plug in the values to the formula

A = 22 * 18 =396

so the area of the last rectangle is 396 ft²

Finally we want to add all of the areas together

396 + 400 + 63 = 859

So the area of the figure is 859 ft²

7 0
3 years ago
Read 2 more answers
Preston has a car washing business. Last year he washed 20 cars a week. This year, he washed 1,200 cars. How many more cars did
kakasveta [241]

Answer:

He washed 160 more cars this year than last year.

Step-by-step explanation:

Last year:  He washed a total of 1,040 cars.

This year:  He washed a total of 1,200 cars.

     1,200

 <u>-   1,040</u>

        160

7 0
3 years ago
The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz
scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at  brainly.com/question/3250070

#SPJ1

4 0
2 years ago
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