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Dafna11 [192]
3 years ago
8

Which law was established to prevent law enforcement agencies from accessing communication through telephone and digital mediums

? A )Children's Online Privacy Protection Act B) California Online Privacy Act C ) Electronic Communications Privacy Act D )The Fair Credit Reporting Act
Computers and Technology
2 answers:
s344n2d4d5 [400]3 years ago
3 0
California Online Privacy act
dalvyx [7]3 years ago
3 0

Answer:

Electronic communications privacy Act ( C )

Explanation:

The Electronic communications privacy Act was established in 1986 which prohibits the interference of telephone conversations of individuals by law enforcement agencies through Wiretapping into the telephone conversations and also the electronic transmission of data

Wire taping into telephone conversation by law enforcement agencies became a problem somewhat in the society because the right to free communication between individuals was breached in most wire taps hence the act was proposed to check and prohibit it. The children's online privacy protection act was meant to protect the privacy of children online.

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Non-Discretionary Items will increase or decrease without any action by Congress or the President. Which of the following is NOT
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<span>A. Military Spending</span>
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4 years ago
Write a class with a constructor that accepts a String object as its argument. The class should have a method that returns the n
mote1985 [20]

Answer:

import java.util.Scanner;

public class VowelsAndConsonantsDemo {

   /**

   The printMenu methods displays a menu to the user

    */

   public static void printMenu() {

       System.out.println("Please select an option: ");

       System.out.println();

       System.out.print("a. Count the number of vowels in the string.\n"

               + "b. Count the number of consonants in the string.\n"

               + "c. Count both the vowels and consonants in the string.\n"

               + "d. Enter another string.\n"

               + "e. Exit the program\n");

   }

   public static void main(String[] args) {

       String input;      // to hold the user's input

       String option;     // to hold the user's input

       char choice;       // to hold a single character

       char exit;         // user chooses 'e' to exit the program

       char letter;       //the Y or N from the user's decision to exit

       // create a Scanner object to read keyboard input.

       //  Scanner keyboard = new Scanner(System.in);

       Scanner keyboard;

       do {

           keyboard = new Scanner(System.in);

           // ask user to enter string

           System.out.print("Enter a string: ");

           input = keyboard.nextLine();

           input = input.toLowerCase();

           System.out.println();

           printMenu();

           option = keyboard.nextLine();

           choice = option.charAt(0);

           VowelsAndConsonants words = new VowelsAndConsonants(input);

           switch (choice) {

               case 'a':

               case 'A':

                   System.out.println("Number of Vowels: " + words.getVowels());

                   break;

               case 'b':

               case 'B':

                   System.out.println("Number of Consonants: " + words.getConsonants());

                   break;

               case 'c':

               case 'C':

                   System.out.println("Number of Vowels & Consonants: " + words.getConsonants()

                           + words.getVowels());

                   break;

               case 'd':

               case 'D':

                   System.out.println("Enter a string: ");

                   break;

               case 'e':

               case 'E':

                   System.exit(0);

                   break;

               default:

                   System.out.println("You did not enter a valid choice.");

           }

           //

           // keyboard.nextLine();    //consumes the new line character after the choice

           // String answer = keyboard.nextLine();

           // letter = answer.charAt(0);

       } while (true);

   }

}

4 0
3 years ago
n channels of bandwidth Bc are multiplexed together with FDM on a link. The guard band between two adjacent channels has bandwid
Andrei [34K]

Answer: The answer to the question is as follows:

Minimum BW= n*Bc + (n-1) Bg

Explanation:

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If we assume no guard bands between the different signals, the mimum bandwidth needed would be n times the bandwidth of a single signal.

In order to avoid crosstalk between signals, as the communication channel is not perfect, it usually leaves some room between any 2 signals, which it is called a band guard, and because there is a band guard for any 2 contiguous signals in the spectrum, the total number of bandguards (Bg) will be equal to (n-1) signals, so the total bandwidth to be used will be as follows:

BW needed: n*Bc + (n-1) Bg.

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4 years ago
For problems 14 – 21 determine all the roots of the given function.
lesya [120]
What’s the problem ?
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scZoUnD [109]

Answer:

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