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melomori [17]
3 years ago
5

Alexa is teaching students to measure and compare the speed of a pencil as it is dropped from different heights

Chemistry
2 answers:
Viefleur [7K]3 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It is because it involves experimentation and observation of the pencil dropping from different heights.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Brut [27]3 years ago
5 0

Answer:

It involves experimentation and observation of the pencil dropping from different heights

Explanation:

Students are being asked to drop the pencil from different heights and to measure the time it takes for a pencil to fall from different heights and then calculate the speed corresponding to each height and measured time. In this scenario the students are doing science as they carrying out experiments and making observations to find a unknown which is the speed of the pencil falling from different heights.

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A sample of gas occupies 10.0 L at 240°C under a pressure of
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Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

T2 = 1099 °C

8 0
3 years ago
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Pcl5 exist but ncl5 does not.why?
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6 0
2 years ago
The theory of plate tectonics is supported
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3 years ago
What type (or two types) of energy is “heat energy on earth escapes into space”?
Gemiola [76]

Answer:

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Explanation:

3 0
2 years ago
To what final concentration of NH3 must a solution be adjusted to just dissolve 0.060 mol of NiC2O4 (Ksp = 4×10−10) in 1.0 L of
ololo11 [35]
Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>

Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48

K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span> 
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M) 
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NH3 = ⁶√0.0075 

NH3 = 0.44 M

3 0
3 years ago
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