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3 years ago

6.

Chemistry

1 answer:

wlad13 [49]3 years ago

6 0

Answer:

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If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h

Kay [80]

At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root:
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769

7 0

3 years ago

For each value of the principal quantum number n, what are the possible values of the electron spin quantum number?

Ede4ka [16]

Answer:

The values for spin quantum number +1/2 and - 1/2

Explanation:

Principal quantum number denoted by (n) is used to describe the shell or orbits that electrons are found. Principal quantum number can assume a value of n= 1,2, 3, 4,5............ which indicates K, L, M, N, O shell respectively.

To know the maximum number of electrons in each shell, the formula (2n²) can be used. The letter 'n' denotes the values of principal quantum number 1,2,3,4

For example

n=1 (K shell) has maximum number of 2 electrons
n=2 (L shell) has the maximum number of 8 electrons
n=3 (M shell) has the maximum number of 18 electrons
n=4 (N shell) has the maximum number of 32 electrons

All the electron in each shell will have a spin quantum number of +1/2 and - 1/2. One electron in each degenerate orbital will spin up (+1/2) while the other electron will spin down (-1/2).

7 0

3 years ago

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of $O_2$

So, 155. mmole of HCl react with $\frac{155.}{4}\times 1=38.75$ mmoles of $O_2$

That means, $O_2$ is excess reagent and $HCl$ is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0

3 years ago

When 21.5 g of CH4 gas reacts with 387.5 g O2 gas, how much CO2 is formed?

Doss [256]

Answer:

Mass = 58.96 g

Explanation:

Given data:

Mass of CH₄ = 21.5 g

Mass of O₂ = 387.5 g

Mass of CO₂ formed = ?

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass / molar mass

Number of moles = 21.5 g/ 16 g/mol

Number of moles = 1.34 mol

Number of moles of O₂ :

Number of moles = mass / molar mass

Number of moles = 387.5 g/ 32 g/mol

Number of moles = 12.1 mol

now we will compare the moles of CO₂ with O₂ and CH₄.

O₂ : CO₂

2 : 1

12.1 : 1/2×12.1 = 6.05 mol

CH₄ : CO₂

1 : 1

1.34 : 1.34

Number of moles of CO₂ produced by CH₄ are less thus it will limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.34 mol × 44 g/mol

Mass = 58.96 g

8 0

3 years ago

Chemical reaction occurs when the chemical identity of the reactants is different from that of the products. A new substance for

nikdorinn [45]

Answer:

Explanation:

Exothermic: the surrounds feel warmer. A wood fire stove is a good example of an exothermic reaction. You can feel the heat on your hands. It's exothermic.

Endothermic is exactly the opposite. The reaction takes place, but the heat comes from the surroundings. When you touch something that goes through an endothermic reaction, it feels much cooler.

This reaction, just by definition is endothermic.

5 0

3 years ago