First, we will get the "n", the number of half lives, it is the elapsed time over the half life. In the problem, the time is measured in days, so we have
6/2 = 3
to get the ending amount of radioactive sample, we have
32g x (1/2)³ = 4 grams of radioactive sample ⇒ the amount left after 6 days
Answer:
0.857 atm
Explanation:
The nitrogen stops owing when it fulfills both of the tanks (the gas molecules intend to fulfill all the space they are). So the tanks will have the same pressure, and the final volume will be the volume of the two tanks.
For Boyle's law:
P1*V1 = P2*V2
Where P1 is the initial pressure (3.00 atm), V1 is the initial volume(2.00 L), P2 is the final pressure, and V2 is the final volume (2.00 + 5.00 = 7.00 L).
3.00*2.00 = P2*7.00
7.00P2 = 6.00
P2 = 0.857 atm
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Answer:
C2H4O2 + 2O2 ==> 2CO2 + 2H2O
Explanation:
Start with the carbons
C2H4O2 + O2 ==> 2CO2 + H2O There are 2 on the left, so you need 2 on the right.
Next deal with the hydrogens. You have 4 on the left so you have to make 4 on the right
C2H4O2 + O2 ==> 2CO2 + 2H2O
The oxygens are the real devil in this question. Be careful how you handle them. There are 2 * 2 = 4 from the CO2 and 2*1 = 2 from the water. The total is 6
Now you can't just put a 3 in front of the O2. There are 2 in the given chemical. So you don't need 6. You need 6 -2 = 4. But the oxygen is O2. You have to divide the 4 by 2 to get 2
C2H4O2 + 2O2 ==> 2CO2 + 2H2O
And that's your answer.
Answer:
13g
Explanation:
34+10+26=70
70-57=13
13g would complete the equation
