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Aliun [14]
3 years ago
5

How could you measure the average kinetic energy of a group of particles

Chemistry
2 answers:
dexar [7]3 years ago
8 0

Answer:

Temperature measures the average kinetic energy of the particles in a substance. Thermal energy measures the total kinetic energy of the particles in a substance. The greater the motion of particles, the higher a substance's temperature and thermal energy.

Explanation:

ElenaW [278]3 years ago
4 0
Oh yeah that’s fine I just got home from school I was crying and I’m getting mad I love it lol I don’t want you anymore I don’t want you
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Which molecule would be harder to break apart, O2 with double bonds or
Sliva [168]

Answer:

neither they both have the same molecule #

Explanation:

5 0
3 years ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
Elements that do not have full outer electron shells will donate, share, or take from other atoms. Choose the items that have th
Gnesinka [82]

Answer:

Ok...

Answer: YTH/JYG

Explanation:

AI+ZN+H=YTH

7 0
3 years ago
Consider this reaction and answer the questions:
Mandarinka [93]

Balanced chemical reaction: 2KClO₃ → 2KCl + 3O₂.

Potassium is metal from first group of Periodic table of elements, it has always oxidation number in compound +1.

Chlorine in the reactant state has oxidation number +5 (+1 + x + 3 · (-2) = 0) and it is reduced to -1 (+1 + x = 0) in the product state.

Oxygen in the reactant state has oxidation number -2 (+1 + 5 + 3 · x = 0) and it is oxidized to 0 (in molecule of oxygen) in the product state.

3 0
3 years ago
Read 2 more answers
Given the molar absorptivity for a species X of 1600 M-1cm-1 at a wavelength of 270 nm, and 400 M-1cm-1 at a wavelength of 540 n
Andre45 [30]

Answer:

Explanation:

From the given information:

At wavelength = 270 nm

\varepsilon x_1 = 1600 \ m^{-1} \ cm^{-1}  \\ \\  \varepsilon y_1 = 200 \ m^{-1} \ cm^{-1}

At 270 nm

Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;

Then:

\varepsilon x_1  \ l + \varepsilon y_1  \ l= 0.5 \\ \\ A = A_1 + A_2

1600 xl + 200 yl= 0.5

Divide both sides by 200

8xl + yl = \dfrac{0.5}{200}

8x + y = \dfrac{0.5}{200}l

Use l = 1cm (i.e the standard length)

Then;

8x + y = \dfrac{0.5}{200} ---- (1)

<u>For 540 nm:</u>

\varepsilon x_2 x  \ l + \varepsilon y_2 y  \ l= 0.5  \\ \\ 40 xl + 800 yl = 0.5

x + 20 y = \dfrac{0.5}{400 \ l}

since l = 1

x + 20 y = \dfrac{0.5}{400 \ } --- (2)

Equating both (1) and (2) together, we have:

8x + y - 8x - 160 y = \dfrac{0.5}{200} - \dfrac{0.5 \times 8}{400}  \\ \\  \implies - 159 y = \dfrac{0.5}{200} ( 1 - \dfrac{8}{2}) \\ \\  -159 y = \dfrac{-0.5 \times 3}{200}  \\ \\  159 \ y = 0.0075  \\ \\  y = \dfrac{0.0075}{159} \\ \\  y = 0.00004716 \\ \\ y = 4.7 \times 10^{-5 } \ M

3 0
3 years ago
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