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KiRa [710]
4 years ago
14

Suppose that AD,BC,AC and BD are line segments with line AD parallel to line BC. If AD=3, BC=1, and the distance from AD to BC i

s 5, then what is the altitude of the smaller triangle?
Mathematics
1 answer:
Semmy [17]4 years ago
4 0

Thank you for posting your question here at brainly. Feel free to ask more questions.  <span>

The best and most correct answer in this question is</span>

<span>(1) h+k=5 </span>

<span>(2)k=3h </span>

<span> h+3h=5 </span>

<span>h= 5/4 or 1.25 units</span>

<span>    
Hope my answer would be a great help for you.</span>

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Santa's elves are selling
Andreas93 [3]

cost of one peppermint cookies = $ 0.6

cost of one cinnamon sugar cookies = $ 0.3

<h3><u>Solution:</u></h3>

Let "p" be the cost of one peppermint cookies

Let "c" be the cost of one cinnamon sugar cookies

<u><em>To find: cost of each cookie</em></u>

<h3><u><em>On  the first day, they sold 120  peppermint cookies and 30  cinnamon sugar cookies for a  total of $81</em></u></h3>

We can frame a equation as:

120  peppermint cookies x cost of one peppermint cookies + 30  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120 \times p + 30 \times c = 81

120p + 30c = 81  --------- eqn 1

<h3><u><em>The next day  they made $60 by selling 70  peppermint cookies and 60  cinnamon sugar cookies</em></u></h3>

70  peppermint cookies x cost of one peppermint cookies + 60  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70 \times p + 60 \times c = 60

70p + 60c = 60 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "c"

Multiply eqn 1 by 2

240p + 60c = 162  --- eqn 3

Subtract eqn 2 from eqn 3

240p + 60c = 162

70p + 60c = 60

(-) -------------------------

170p = 102

<h3>p = 0.6</h3>

Substitute p = 0.6 in eqn 1

120p + 30c = 81

120(0.6) + 30c = 81

72 + 30c = 81

30c = 9

<h3>c = 0.3</h3>

<u><em>Summarizing the results:</em></u>

<em>cost of one peppermint cookies = $ 0.6</em>

<em>cost of one cinnamon sugar cookies = $ 0.3</em>

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The graph of an absolute value function opens down and has a vertex of (0, -3). The domain of the function is . The range of the
Firdavs [7]

Answer:

Domain: All real numbers

Range: y\leq -3

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is y\leq -3

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Answer:

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Step-by-step explanation:

The area (A) of a rhombus can be calculated using

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A = \frac{1}{2} × 24 × 25 = 300 ft²

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Answer:68-35

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