For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
Not sure but It should be -4/1
Slope intercept: y = mx + b
3y = 2x + 10
Y = 2/3x + 10/3
Perpendicular = opposite sign and reciprocal slope
Y = -3/2x + b
-10 = -3/2(10) + b
-10 = -15 + b, b = 5
Equation: y = -3/2x + 5
1 1/4 because you must make improper fractions
Answer:
x = -0.69
Step-by-step explanation:
We can get this by writing the equation in the logarithmic form to base e
We have this as;
log e 0.5 = x
x = ln 0.5
x = -0.69315
To two decimal places, this is -0.69
