<u>Given Equation</u>:-
- 5x+y=17 . . . . . . . . 1
- x+y=3 . . . . . . . . . . 2
<u>To find</u> :
<u>Solution</u> :
<u>Let's start with equation 2</u>:-
x + y = 3
y = 3 - x
Put the value of y in Equation 1
- 5x+y=17
- 5x + (3 - x) = 17
- 5x - x + 3 = 17
- 4x + 3 = 17
- 4x = 17 - 3
- 4x = 14
- x = 14/4
- x = 7/2
- x = <em>3.5</em>
<u>Now Let's find value of y</u><u>:</u>
put the value of x in equation 2:
y = 3 - x
y = 3 - 3.5
y = <em>0.5</em>
Answer:
He must lose 4.4 pounds per week.
Step-by-step explanation:
Buffalo Bill currently weighs 202 lb. He wants to weigh 180 lbs for his reunion.
This means that he needs to lose 202 - 180 = 22 lb.
35 days from today.
Each week has 7 days. So this is 35/7 = 5 weeks from now.
How many pounds per week must he lose?
22 pounds in 5 weeks, that is 22/5 = 4.4 pounds per week.
Answer:
w = 12
Step-by-step explanation:
3w = 11 + 25
3w = 36
w = 12
Hope that helps!
A=7,500×(1+0.06÷4)^(4×2)
A=8,448.69
Interest earned=8,448.69−7,500
Interest earned=948.69
Answer:
Option A
The p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
Step-by-step explanation:
Normally, in hypothesis testing, the level of statistical significance is often expressed as the so-called p-value. We use p-values to make conclusions in significance testing. More specifically, we compare the p-value to a significance level "α" to make conclusions about our hypotheses.
If the p-value is lower than the significance level we chose, then we reject the null hypotheses H0 in favor of the alternative hypothesis Ha. However, if the p-value is greater than or equal to the significance level, then we fail to reject the null hypothesis H0
though this doesn't mean we accept H0 automatically.
Now, applying this to our question;
The p-value is 0.023 while the significance level is 0.05.
Thus,p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
The only option that is correct is option A.