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jonny [76]
3 years ago
14

PLEASE HELP, Urgent

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
You do in fact get a negative number so the solutions are not real but imaginary.  Good!
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Solve the equations
Minchanka [31]

Answer:

#1 - All real numbers are solutions.

#2 - All real numbers are solutions.

Step-by-step explanation:

#1 -

Let's solve your equation step-by-step.

12(6t−4)=3t−2

Step 1: Simplify both sides of the equation.

12(6t−4)=3t−2

(12)(6t)+(12)(−4)=3t+−2(Distribute)

3t+−2=3t+−2

3t−2=3t−2

Step 2: Subtract 3t from both sides.

3t−2−3t=3t−2−3t

−2=−2

Step 3: Add 2 to both sides.

−2+2=−2+2

0=0

Same for #2

8 0
3 years ago
I don’t really understand this
PtichkaEL [24]

Answer:

you put the -3 where the x's are

Step-by-step explanation:

f(x)= -2(-3)^2 - 3(-3) + 6

i think i hope thats right

3 0
3 years ago
Read 2 more answers
What is th quotenit for r an 12
kramer
Having The Lack Of Information, We Can Only Give You An Equation. 

So:

Quotient = Division.

R / 12 Is The Equation.

(If This Is Not What You Need, Put In More Info, And I Can Solve It. ;) <span />
6 0
2 years ago
Read 2 more answers
Helpppppp mathhh failing
LenKa [72]
Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2  = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5

sin30 = b/a
1/2 = 5√3  / a

a = 5√3 (2)
a = 10√3

c^2 = (10√3)^2  -  (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15

so
a =10√3,  b = 5√3, c = 15,d = 5
answer is
D. last choice

4 0
3 years ago
Can someone help me with this one please ? Thanks!
inysia [295]
I hope this helps you

4 0
3 years ago
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