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aev [14]
3 years ago
11

An instructor gives a class a set of 10 problems and says that the nal exam will consist of a random selection of 5 of the probl

ems. If a student has gured out how to solve 7 of the problems, what is the probability that he or she will answer at least 4 problems correctly?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer:

probability that he or she will answer at least 4 problems correctly = 0.5

Step-by-step explanation:

probability that he or she will answer at least 4 problems correctly is given as;

P (at least 4 correctly) = P (exactly 4 correctly) + P (all 5 correctly)

Since there are 10 problems. 4 is from the 7 problems chosen and 1 is from the 3 problems we can't figure out. Thus, P(exactly 4 correctly) = 7C4 x 3C1

Thus, P (at least 4 correctly) = [ (7C4) x (3C1) ] / (10C5)] + [(7C5)/(10C5)]

= [(35 x3)/252 ] + [21/252]

= [ 105/252 ] + [ 21/252 ]

= 126 / 252

= 0.5

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Fun, geometry disguised as probability.

That's a pentagon, which we can view as 10 right triangles with legs a and s/2 (half of s) and hypotenuse r.  So area of the pentagon is

P = 10 × (1/2) a (s/2) = 10 (1/2) (3.2) (4.7/2) = 37.6

The area of the circle is πr² so the circle area is

C = π (4²) = 50.265482

The white area is the difference, C-P, and the probability we seek is the fraction of the circle that's white, so (C-P)/C.

p = (C-P)/C =1-P/C = 1-37.6/50.265482 = 0.251971

Answer: 0.25

Higher than I would have guessed from the figure.

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3 years ago
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Artyom0805 [142]
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Answer:

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Step-by-step explanation:

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