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kifflom [539]
2 years ago
11

What will be the smallest and largest no that when rounded off to thousand their answer is

Mathematics
2 answers:
Tatiana [17]2 years ago
6 0

Answer:

1a- 784500 & 785499

b- 4528499 & 4527500

2a- 23749 & 23650

b- 429949 & 429850

3a- 6445 & 6454

b- 88885 & 88894

Softa [21]2 years ago
4 0

Answer:

A,785000

B,429900

A,6450

You might be interested in
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
Trig///HELPP PLEASE!! i’ve been stuck on this for 30 minutes!!
ddd [48]

Answer: There are two solutions and they are

theta = 135

theta = 225

=============================================================

Explanation:

Recall that x = cos(theta). Since the given cosine value is negative, this indicates x < 0. Theta is somewhere to the left of the y axis, placing it in quadrant 2 or quadrant 3.

It turns out there are two solutions, with one solution per quadrant mentioned above. Use the unit circle to find that the two solutions are:

theta = 135

theta = 225

You're looking for points on the unit circle that have x coordinate equal to x = -sqrt(2)/2. Those two points correspond to the angles of 135 and 225, which are in quadrants 2 and 3 respectively.

--------

I recommend using your calculator to note that

-sqrt(2)/2 = -0.70710678

cos(135) = -0.70710678

cos(225) = -0.70710678

The decimal values are approximate. Make sure your calculator is in degree mode. Because those three results are the same decimal approximation, this indicates that cos(135) = cos(225) = -sqrt(2)/2.

8 0
3 years ago
If QN bisects PQR and N is THE midpoint of PR classifiy each triangle by its angles and sides
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What is the value of x?
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1. The value of x is 4. X + 4 = 4 + 4 = 8
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The answer would 3X3X7
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