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just olya [345]
3 years ago
12

Please help me I need help

Mathematics
1 answer:
amid [387]3 years ago
8 0

Answer:

f(6)=2

f(2)=4

f(0)=7

f(5)=1.5

Step-by-step explanation:

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Solve for the values of x and y in the diagram
qaws [65]

Answer: y = 0.5, x = 50

Step-by-step explanation: Both triangles in the picture are isosceles, telling us that the 2 angles at the bottom are congruent. With this, we can find y by doing the following:

a triangle has 180 degrees so we subtract the given 50 which gives us 130

2(2y + 64) = 130

4y + 128 = 130

y = .5

This means that the bottom 2 angles are both 65. Since the top angle of the second triangle is supplementary to the bottom angle of the first one, the top angle of the second triangle is 115. So, we find x by:

2(45 - x/4) = 65

x = 50

This means the bottom 2 angles of the second triangle are both 32.5.

7 0
3 years ago
Read 2 more answers
DUE TODAY!!!! I WILL MARK BRAINLIST
11Alexandr11 [23.1K]
Median: 3
mode: 3
range: 9
interquartile range: 2

the outliers are 9 and 5. there is a cluster between 2 and 3.
5 0
3 years ago
EDIT// answer below thank for the help -.-
HACTEHA [7]

Step-by-step explanation:

Move it it up 4 and then find your x intercepts.

Find the x intercepts.

-x^2 + 4 = 0

<u>Move the 4 over to the right</u>

-x^2 = -4

<u>Divide out the - </u>

\frac{-x^2}{-} = \frac{-4}{-}

x^2 = 4

<u>Take the square root of each side</u>

\sqrt{x^2} = \pm \sqrt{4}

x = \pm \sqrt 2

Our x intercepts are at (-2,0) (2,0)

8 0
4 years ago
Three vertices of the trapezoid are A(4d,4e), B(4f,4e), and C(4g,0). The fourth vertex lies on the origin. Find the midpoint of
satela [25.4K]
We have that

point C and point D have y = 0-----------> (the bottom of the trapezoid).

point A and point B have y = 4e ---------- > (the top of the trapezoid)

the y component of  midpoint would be halfway between these lines
 y = (4e+ 0)/2 = 2e. 

<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.

x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g. 

</span>therefore

the midpoint of the midsegment is (d + f + g, 2e)
8 0
3 years ago
6 of 8
Masja [62]

Answer:

\frac{19}{4}

Step-by-step explanation:

\frac{5 + 4 + 6 + 6 + 5 + 5 + 4 + 3}{8}

=38/8

=19/4

4 0
3 years ago
Read 2 more answers
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