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Mars2501 [29]
3 years ago
12

MULTIPLE CHOICE PLS ANSWER

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

Option.B

Step-by-step explanation:

Its because if you add these two angles you get a supplementary angle or 180°

Using this we can form an equation to find the value of x.

(Hope this answer helps :))

(And is this question from Khan Academy?)

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What is the value of x? enter your answer in the box​
nekit [7.7K]

Answer:

x=7

Step-by-step explanation:

6x6=36

6x7=42

Sides of the right triangle are 6x bigger

8 0
2 years ago
A quarterback throws a football with a velocity of 41 mph and a direction of 168°. The wind on the field is 11 mph with a direct
Cerrena [4.2K]

The true speed and direction of the football thrown by the  quarterback is 30.185 mph and 9⁰ respectively.

<h3>Relative velocity of the football</h3>

The true speed and direction of the football is determined by applying the concept of relative velocity.

Vr/w = Vb - Vw

where;

  • Vr/w is the velocity of the football with respect to the wind
  • Vb is the velocity of the football
  • Vw is the velocity of the wind

Vr/w = 41 mph - 11 mph = 30 mph

The direction speed can be determined by sketching a triangle

Direction of the speed, θ = (360 - 339) - (180 - 168)

                                       θ = 21 - 12 = 9⁰

<h3>Resultant speed;</h3>

R² = 41² + 11² - 2(41 x 11 x cos9)

R² = 911.105

R = √911.105

R = 30.185 mph

Thus, the true speed and direction of the football thrown by the  quarterback is 30.185 mph and 9⁰ respectively.

Learn more about relative velocity here: brainly.com/question/17228388

#SPJ1

8 0
2 years ago
Write an expression that equals 56. Include an exponent.
Troyanec [42]

There are many possibilities. An example is 1^{1} + 55 = 56.

6 0
3 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
Math hw write an expression step by step
FrozenT [24]
Look it up on google man
8 0
3 years ago
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