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Ratling [72]
3 years ago
9

Every computer consists of physical components and nonphysical components. the nonphysical components of a computer that underst

and how to work with the physical components are referred to as
Computers and Technology
1 answer:
IrinaVladis [17]3 years ago
7 0
Physical component means Computer Hardware which you can touch and non Physical component means Software, which you can not touch. nonphysical component designed specially for physically component. like Microsoft company designed Software according the Hardware for example Microsoft windows 64 bit could not install on which 32 bit Architecture Hardware.
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Write a function (subroutine) that inputs a data value in register r0 and returns value in r0. The function returns y 5 a 1 bx 1
umka2103 [35]

Solution :

  int f(int x){

      \text{return a + b*x +c*x*x};

  }*/

  int f(\text{int R0}){

      int stack[2] = {\text{R1,R2}};

      \text{R1 = R0};

      \text{R1 = R1}\times \text{ R1};

      \text{R2 = C};

      R1 = R1 * C; /*R1 = cx^2*/

      \text{R2 = B};

      \text{R0 = R0} * R2; /* R0 = bx */

      \text{R0 = R0 + R1}; /*R0 = bx + cx^2 */

      \text{R2 = C};

      \text{R0 = R0 + R2}; /*R0 = a+bx+cx^2 */

      \text{R1 = stack[0];}

     \text{ R2 = stack[1];}

     \text{ return R0;}

  }

  /*\text{ARM code to implement the following C operation}

  int s=0;

  \text{for ( i = 0; i < 10; i++)}

  { \text{s = s + i } \times i;)

  */

          AREA SumSquares, code, readWrite

          ENTRY

          \text{MOV r0, #0}        ;loop \text{ counter i present at 0}

          MOV r1, #0       ; s = 0

  Loop   \text{MUL r2, r0, r0}   ;calculate i*i

          \text{ADD r1, r1, r2}   ;s = s+ i*i

          \text{ADDS r0, r0}, #1   ; i = i+1

          \text{CMP r0},#10       ; test for end

          \text{BNE} Loop        ; \text{continue until all added}

          END

5 0
3 years ago
Larry does not want to save his Internet browsing details on his computer what files delete to clear his information from the co
GREYUIT [131]
He would have to clear his history or use incognito tabs from then on.
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4 years ago
Suggest three ways in which celebrating an occasion influences food choices?
Basile [38]

Celebrating influences food in more than 1 way
6 0
3 years ago
Read 2 more answers
Which library research databases include information about articles published in magazines, journals, and newspapers? question 1
Alecsey [184]

Answer:

periodical databases

Explanation:

Among the various databases you can now access in a library, the periodical databases contains the text and other information about articles published in magazines, journal and newspapers.

This database allows you for example to easily search for all articles written about a specific event or person, and it will return you the list of articles you can then read from a single spot, no matter where or when the article was written.

8 0
3 years ago
Write an assembly language program with a loop and indexed addressing that calculates the sum of all the gaps between successive
PSYCHO15rus [73]

Answer:

Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.

;Include Irvine32.inc file used with link library for 32 bit applications

.386

.model flat,stdcall

.stack 4096

ExitProcess proto,dwExitCode:dword

INCLUDE Irvine32.inc

.data

myArray DWORD 0,2,5,9,10

arrSize = ($-myArray)/TYPE myArray

gapArr DWORD arrSize-1 DUP(?)

sum DWORD ?

.code

main PROC

;Call the procedure

call Clrscr

;Initialize ESI pointer

mov esi, 0

mov ecx, arrSize

dec ecx

L1:

mov eax, myArray[esi+4]

sub eax, myArray[esi]

mov gapArr[esi], eax

inc esi

loop L1

;Calculate the sum of gaps between array elements

mov sum, 0

mov esi, 0

mov ecx, arrSize

dec ecx

;  move gapArr[esi] to a temporary register and then add that register value to sum

L2:

mov edx, gapArr[esi]  

add sum, edx

inc esi

loop L2

       INVOKE ExitProcess,0

main ENDP

END main

Explanation:

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