Solution :
int f(int x){
;
}*/
int f(
){
int stack[2] = {
};
;
;
;
R1 = R1 * C; /*R1 =
*/
;
* R2; /* R0 = bx */
; /*R0 =
*/
;
; /*R0 = a+bx+cx^2 */
}
/*
int s=0;
{
;)
*/
AREA SumSquares, code, readWrite
ENTRY
;loop
MOV r1, #0 ; s = 0
Loop
;calculate i*i
;s = s+ i*i
, #1 ; i = i+1
,#10 ; test for end
Loop ;
END
He would have to clear his history or use incognito tabs from then on.
Celebrating influences food in more than 1 way
Answer:
periodical databases
Explanation:
Among the various databases you can now access in a library, the periodical databases contains the text and other information about articles published in magazines, journal and newspapers.
This database allows you for example to easily search for all articles written about a specific event or person, and it will return you the list of articles you can then read from a single spot, no matter where or when the article was written.
Answer:
Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.
;Include Irvine32.inc file used with link library for 32 bit applications
.386
.model flat,stdcall
.stack 4096
ExitProcess proto,dwExitCode:dword
INCLUDE Irvine32.inc
.data
myArray DWORD 0,2,5,9,10
arrSize = ($-myArray)/TYPE myArray
gapArr DWORD arrSize-1 DUP(?)
sum DWORD ?
.code
main PROC
;Call the procedure
call Clrscr
;Initialize ESI pointer
mov esi, 0
mov ecx, arrSize
dec ecx
L1:
mov eax, myArray[esi+4]
sub eax, myArray[esi]
mov gapArr[esi], eax
inc esi
loop L1
;Calculate the sum of gaps between array elements
mov sum, 0
mov esi, 0
mov ecx, arrSize
dec ecx
; move gapArr[esi] to a temporary register and then add that register value to sum
L2:
mov edx, gapArr[esi]
add sum, edx
inc esi
loop L2
INVOKE ExitProcess,0
main ENDP
END main
Explanation: