Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
Answer:
1, if solved for x = 6 - 4y/3 & y = 9/2 - 3x/4
2, x = -4 + 2y & y = 2 + x/2
Step-by-step explanation:
Answer:
they need to sell 13 pizzas
Step-by-step explanation:
20% u change it to 0.20
0.20 × 65 = 13
Answer:
52.48x ≤ 288.64
x≤5.5, x=5
Step-by-step explanation:
First off, we must find out how much money he has available after buying the bike, reflectors and gloves:
Total spent = (price of bike)+3(price of reflectors)+(price of gloves)
=233.09+3(16.38)+29.13
=311.36
600-311.36=288.64, so he has $288.64 left to spend on outfits.
The cost of x amount of outfits is found by multiplying the amount of outfits, x, by the cost per outfit, 52.48: 52.48x. Since he can only spend up to $288.64, 52.48x must be less than or equal 288.64:
52.48x ≤ 288.64
To solve, divide both sides by 52.48:
x≤5.5
(Since he cant buy half of a product, x's maximum value is 5)
28/4=7
so 7 stickers were on each sheet