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3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics

2 answers:

Helen [10]3 years ago

3 0

Answer:

7 seconds

Step-by-step explanation:

Hello There!

I had created a graph to make it easier to understand

So when y = 0 is when the ball is at the ground

when y = 0 x = 7 so it took about 7 seconds for the ball to hit the ground

Lady bird [3.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

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Find the equation of the linear function represented by the table below in slope-

pav-90 [236]

Answer: $y=-3x-2$

Step-by-step explanation:

Using the values $x=-2, y=4$ and $x=1, y=-5$ , the slope is $\frac{-5-4}{1-(-2)}=-3$ .

So, the equation is:

$y-4=-3(x+2)\\\\y-4=-3x-6\\\\y=-3x-2$

3 0

1 year ago

(A) {(-6,2), (3, 4), (4,4), (5, 6)} DOMAIN: RANGE: Is the relation above a function?

vovikov84 [41]

Answer:

Yes

Step-by-step explanation:

Domain: {-6, 3, 4, 5}

Range: {2, 4, 6}

This relation is a function.

6 0

3 years ago

Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with

yan [13]

Answer:

The volume of pyramid B is 64 times the volume of pyramid A.

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

Volume of pyramid A:

$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$