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4 years ago

Which equation correctly determines the amount of material used, M, to construct the fully enclosed tent?

Mathematics

1 answer:

goldenfox [79]4 years ago

3 0

Answer:

B) M = (8 x 9) + 2 x (7.5 x 8) + 2 x ( 1/2 x 9 x 6)

Step-by-step explanation:

Triangular prism area:

B) M = (8 x 9) + 2 x (7.5 x 8) + 2 x ( 1/2 x 9 x 6)

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Is the following function (c) even, odd, or neither? Why?

AVprozaik [17]

Answer:

The function is odd.

Step-by-step explanation:

Test to determine if a function y = f(x) is even, odd or neither: replace x with -x and compare the result to f(x). If f(-x) = - f(x), the function is odd. In this case, f(-x) does equal -f(x), so the function is odd.

If this answer is correct, please make me Brainliest!

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3 years ago

What is 52/100 in simplest form

Sonbull [250]

52/100
26/50
13/25
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4 years ago

Read 2 more answers

Seth needs to buy mulch to cover a circular garden. The garden has a radius of 5ft. Mulch costs $0.25 per square foot. How much

Tanya [424]

Answer:

?????

Step-by-step explanation:

12x 0.25=? ?x 5= $?

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3 years ago

Apply the distributive property to write an equivalent expression.

aleksley [76]

Answer:

6x + 48

Step-by-step explanation:

multiply each term inside the () by 6

6x + 6*8

7 0

4 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

4 years ago