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blondinia [14]
3 years ago
10

write the equation x^2 + 4y^2 - 6x - 7=0 in the standard form. state whether the graph is a parabola, circle, ellipse, or hyperb

ola.
Mathematics
1 answer:
Verizon [17]3 years ago
8 0
X^2  + 4y^2 - 6x = 7

x^2  - 6x + 9  + 4y^2  = 16

(x-3)^2/16 + y^2/4 = 1

The graph is an ellipse

hope this helps
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Given that the line y=c-2x is tangent to the curve y^2=kx where c and k are non-zero constants,express k in terms of c
Viktor [21]

Answer:

k = -8c.

Step-by-step explanation:

y^2 = kx

Find the slope of the tangent by differentiating:

y' 2y = k

y' = k / 2y = the slope of the tangent.

The given equation of the tangent is y = -2x + c so the slope = -2.

Therefore  k/2y =  -2  so k = -4y and y = -k/4

y^2 = kx so k^2/16 = kx giving x = k/16.

Substituting for x and y in y = -2x + c:

-k/4 = -2 k/16 + c

-k/4 = -k/8  + c

c = -k/4 + k/8 = -k/8.

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PilotLPTM [1.2K]

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What is an equation of the line that passes through the points (-4, -5) and<br> (-2, – 6)?
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Step-by-step explanation:

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Answer:

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