Ask question

Ask question

All categories

3 years ago

11

Juvi is baking oatmeal raisin cookies and fudge brownies! To make 4 batches of brownies, Juvi needs 2/3 of a cup of sugar. She a

lready has 1/2 of a cup of sugar in her cabinet and her sister Evi brings her 2/5 of a cup of sugar when she hears she needs more! Will Juvi have enough sugar to make 4 batches of brownies? If she does not have enough, how much more does she need? Explain below.**PLEAE HELP WILL MARK BRAINLIEST.

1 answer:

dsp733 years ago

3 0

We can add the fractions together to compare with how much sugar she needs.

$\frac{1}{2}+\frac{2}{5}=\frac{5}{10}+\frac{4}{5}=\frac{9}{10}$

So Juvi has $\frac{9}{10}$ cups of sugar.

She needs $\frac{2}{3}$ cups, so let's make the denominators the same and compare.

$\frac{2}{3}=\frac{20}{30}$

$\frac{9}{10}=\frac{27}{30}$

Since $\frac{27}{30}$ > $\frac{20}{30}$ , she has enough sugar to make 4 batches of brownies.

Hope this helps.

頑張って!

You might be interested in

What is the Domain and Range of the function f(x)<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx-7%7D%20%2B9" id="TexFormula1" tit

omeli [17]

For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}

<h3>How to get the domain and range?</h3>

Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:

x - 7 ≥ 0.

Solving for x we get:

x ≥ 0 + 7

Then the domain is:

x ≥ 7

To get the range, we evaluate in the minimum of the domain:

f(7) = √(7 - 7) + 9 = 9

Then the range is the set of all values larger than 9, because the function is increasing.

So the range is R: y ≥ 9.

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

5 0

2 years ago

NARA [144]

Ans(a):

Given function is $f(x)=\frac{3x-1}{x+4}$

we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0

so let's solve

x+4≠0 for x

x≠0-4

x≠-4

Hence at x=4, function can't have solution.

Ans(b):

We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)

so we get:

g(x)=f(x)+4

$g(x)=\frac{3x-1}{x+4}+4$

We may simplify this equation but that is not compulsory.

Comparision:

Graph of g(x) will be just 4 unit upward than graph of f(x).

Ans(c):

To find value of x when g(x)=8, just plug g(x)=8 in previous equation

$8=\frac{3x-1}{x+4}+4$

$8-4=\frac{3x-1}{x+4}$

$4=\frac{3x-1}{x+4}$

$4(x+4)=(3x-1)$

$4x+16=3x-1$

4x-3x=-1-16

x=-17

Hence final answer is x=-17

8 0

3 years ago

umka21 [38]

Answer:

27.5 mm

Step-by-step explanation:

The game piece has the shape of two identical square pyramids attached at their bases. Given that the perimeters of the square bases are 80 millimeters, and the slant height of each pyramid is 17 millimeters.

Let the side length of each of the side of the base of the pyramid be b, hence:

perimeter = 4b

80 = 4b

b = 20 mm. half of the side length = b/2 = 20 / 2 = 10 mm

The slant height (l) = 17 mm, Let h be the height of one of the pyramid, hence, using Pythagoras theorem:

(b/2)² + h² = l²

17² = 10² + h²

h² = 17² - 10² = 189

h = √189

h = 13.75 mm

The length of the game piece = 2 * h = 2 * 13.75 = 27.5 mm.

6 0

3 years ago

I don't understand the first one.

Mekhanik [1.2K]

No the 6 times 8 is 48 and the 9 times 12 is 108

8 0

3 years ago

Read 2 more answers

Given f(x)=-1/7√16-x^2 find f^-1(x)

Vera_Pavlovna [14]

Answer:

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

Not a function.

Step-by-step explanation:

The given function is;

$f(x)=-\frac{1}{7}\sqrt{16-x^2}$

Let $y=-\frac{1}{7}\sqrt{16-x^2}$

Interchange x and y;

$x=-\frac{1}{7}\sqrt{16-y^2}$

Solve for y;

$-7x=\sqrt{16-y^2}$

Square both sides

$(-7x)^2=(\sqrt{16-y^2})^2$

$49x^2^2=16-y^2$

$49x^2^2-16=y^2$

$y=\pm \sqrt{49x^2-16}$

The inverse is

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

$f^{-1}(x)=\pm \sqrt{49x^2-16}$ is not a function because one x-value maps onto to different y-values.

6 0

3 years ago