Answer:
$30
Step-by-step explanation:
Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same
Based on the information given let x be the number of ticket to be purchased .
Carnival T entrance fee= $7.00
Ride= $0.50 per ticket
Carnival Q entree fee =12.00
Ride= $0.25 per ticket
Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)
.25 x = 5.00
Hence:
x=$.25+$5.00
×=$30
Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30
Answer:
The probability that there will be a total of 7 defects on four units is 0.14.
Step-by-step explanation:
A Poisson distribution describes the probability distribution of number of success in a specified time interval.
The probability distribution function for a Poisson distribution is:
![P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D%2C%20x%3D0%2C1%2C2%2C3%2C...)
Let <em>X</em> = number of defects in a unit produced.
It is provided that there are, on average, 2 defects per unit produced.
Then in 4 units the number of defects is,
.
Compute the probability of exactly 7 defects in 4 units as follows:
![P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D%5C%5CP%28X%3D7%29%3D%5Cfrac%7Be%5E%7B-8%7D8%5E%7B7%7D%7D%7B7%21%7D%5C%5C%3D%5Cfrac%7B0.0003355%5Ctimes2097152%7D%7B5040%7D%5C%5C%20%3D0.1396%5C%5C%5Capprox0.14)
Thus, the probability of exactly 7 defects in 4 units is 0.14.
Assuming the side lengths did not change, ...
Angle C would need to decrease by the same amount.
Angles B and D would each need to increase by the amount angle A decreased.