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Stells [14]
4 years ago
5

A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles. HINT [See Example 7.] H

ow many sets of seven marbles include at least one yellow one but no green ones
Mathematics
1 answer:
lapo4ka [179]4 years ago
3 0

Answer: 8

Step-by-step explanation:

Given: A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles.

Total marbles other than green = 8

Total marbles other than green and yellow = 6

Then the number of sets of seven marbles include at least one yellow one but no green ones:-

^{2}C_1\times^{6}C_6+ ^2C_2\times^6C_5\\\\= 2\times 1+1\times6\\\\=2+6=8

Number of sets of seven marbles include at least one yellow one but no green ones = 8

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Half the sum of X and Y decreased by 1/3 why
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What is the question here.
(1/2)(X+Y)-(1/3)

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Multiply (−4)(−2)(−5)<br><br> A. -40<br><br> B. -8<br><br> C. 8 <br><br> D. 40
wlad13 [49]
(-4)(-2)= 8
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8 0
3 years ago
29 is what percent of 20?
Vanyuwa [196]
29 percent = 29/100
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3 years ago
Which expression is equivalent to (–3y – x) – (5y – 8x)? –8y – 8x –8y 7x 2y – 7x 8y 8x.
IRINA_888 [86]

The expression is equivalent to -8y + 7x.

Given

Expression; (-3y - x) - (5y - 8x)

<h3>How to find the equivalent expression?</h3>

To find the equivalent expression multiply the expression and add and simplify.

Then,

The expression is equivalent to;

 (-3y - x) - (5y - 8x)

-3y - x - 5y + 8x

-8y + 7x

Hence, the expression is equivalent to -8y + 7x.

To know more about expression click the link given below.

brainly.com/question/13040575

6 0
2 years ago
You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co
alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

P=2x+2y

On the other hand, since the available money to buy fence is D dollars,

\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}

Furthermore, the area of the enclosed land is given by

A=xy

Solving the second equation for x,

\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}

Substituting into the equation for the area,

\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}

To find the maximum possible area, solve A'(y)=0, as shown below

\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}

Therefore, the corresponding value of x is

\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}<h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2>\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}<h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0
1 year ago
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