Question

The expression 2x(3x^2-4x)+3(x^2-4x+6) can be written in the form ax^3 + bx^2 + cx + d.

Answer 1

Answer:

$2x(3 {x}^{2} - 4x) + 3( {x}^{2} - 4x + 6) \\ 6 {x}^{3} - 8 {x}^{2} + 3 {x}^{2} - 12x + 18 \\ 6 {x}^{3} - 5 {x}^{2} - 12x + 18$

$a = 6 \\ b = -5 \\ c =- 12 \\ d = 18$