Answer:
<h2>
4076.56</h2>
Step-by-step explanation:
First we need to calculate the James monthly charges on his balance of 4289.
Using the simple interest formula;
Simple Interest = Principal * Rate * Time/100
Principal = 4289
Rate = 5%
Time = 1 month = 1/12 year
Simple interest = 4289*5*1/12*100
Simple interest = 21,445/1200
Simple interest = 17.87
<u>If monthly charge is 17.87, yearly charge will be 12 * 17.87 = </u><u>214.44</u>
The balance on his credit card one year from now = Principal - Interest
= 4289 - 214.44
= 4076.56
The balance on his credit card one year from now will be 4076.56
The answer is 28.26 because to find the area of a circle you need to do pie time radius squared.
do you have a picture of the border?
Answer:

Step-by-step explanation:
A parabola is written in the form
(1)
where:
is the x-coordinate of the vertex of the parabola
is the y-coordinate of the vertex of the parabola
is a scale factor
For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:
(2)

From this last equation, we get that
(3)
Substituting (2) and (3) into (1) we get the new expression:
(4)
We also know that the parabola contains the point (2,-1), so we can substitute
x = 2
f(x) = -1
Into eq.(4) and find the value of k:

So we also get:

So the equation of the parabola is:
(5)
Now we want to rewrite it in the standard form, i.e. in the form

To do that, we simply rewrite (5) expliciting the various terms, we find:

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
Read more about parabola at:
brainly.com/question/1480401
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