The next step Juan will take is to multiply the second fraction by (x-2)/(x-2).
Given that Juan needs to rewrite this difference as one expression (3x/(x²-7x+10))-(2x/(3x-15)) and factor the denominator as (3x/(x-2)(x-5))-(2x/3(x-5)).
An algebraic expression in mathematics is an expression composed of variables and constants and algebraic operations (addition, subtraction, etc.). Expressions are made up of concepts.
The given expression is (3x/(x²-7x+10))-(2x/(3x-15))
Firstly, we will factored the denominator as
(3x/(x-2)(x-5))-(2x/3(x-5)).
Now, we will multiply and divide the second fraction by (x-2), we get
(3x/(x-2)(x-5))-((2x(x-2))/3(x-5)(x-2)).
Hence, the next step when subtracting these expressions (3x/(x-2)(x-5))-(2x/3(x-5)) is multiply the second fraction by (x-2)/(x-2).
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Answer:
c=13/15 riiiiiiiiggggghhhhhhhttttt
Answer:
So, how do we check to see if two functions are inverses of each other? Well, we learned before that we can look at the graphs.
Step-by-step explanation:
Remember, if the two graphs are symmetric with respect to the line y = x (mirror images over y = x ), then they are inverse functions.
<span>For this case we have the following functions transformation:
Vertical expansions:
To graph y = a * f (x)
If a> 1, the graph of y = f (x) is expanded vertically by a factor a.
f1 (x) = (3x) ^ 2
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
f2 (x) = (3x-6) ^ 2
Vertical translations
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
g (x) = (3x-6) ^ 2 + 3
Answer:
expanded horizontally by a factor of 3, horizontal shift rith 6, vertical shift up 3</span>
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is
, and its volume is
. We also know that the area of the larger figure is
; since we don't now its volume, lets represent it with
:
We can conclude that the volume of the larger figure is
; therefore, the correct answer is
a.
