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murzikaleks [220]
3 years ago
14

The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volu

me of the larger figure?
a. 360 in3
b. 300 in3
c. 432 in3
d. 145 in3
Mathematics
2 answers:
Anna71 [15]3 years ago
8 0

Answer:360

Step-by-step explanation:

Slav-nsk [51]3 years ago
6 0
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is 25in^{2}, and its volume is 250in^{3}. We also know that the area of the larger figure is 36in^{2}; since we don't now its volume, lets represent it with X:
\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} 
\frac{25}{36} = \frac{250}{X}
X= \frac{(250)(36)}{25}
X=360

We can conclude that the volume of the larger figure is 360in^{3}; therefore, the correct answer is a.
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Dmitry [639]

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Step-by-step explanation:

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3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
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5 0
3 years ago
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OleMash [197]

Answer:

x^2-11/-8x

Step-by-step explanation:

We can solve this equation easily by using PEMDAS, or order of operations.

<u>Parenthesis</u>

<u>Exponents</u>

<u>Multiplication>Division (Depends on which comes first left to right)</u>

<u>Addition>Subtraction (See multiplication>division)</u>

Now that we know the order of the operations, we can solve.

First, we cant solve for x^2 because we dont know the value of x, so well leave that alone. Same with 22/x. All we can do is use the commutative property.

So our equation is now x^2-11/-8x

Hope this helps!

6 0
3 years ago
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