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3 years ago

Figure A is a scale image of figure B. What is the value of x?

Mathematics

1 answer:

anyanavicka [17]3 years ago

6 0

Answer:

The value of x = 20.

Step-by-step explanation:

Figure B is the scale image of A.

It is clear that:

side 10 of figure A has the image side of 12.5 in figure B.

which can be obtained by multiplying 10 with 1.25

i.e.

10*1.25=12.5

so the side 16 of figure A must have to be multiplied by 1.25 to get the image the figure B.

16*1.25=20

Therefore, the value of x = 20.

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Vlad1618 [11]

Answer:

A = 16 13unit^2 + 9unit^2 = 5 √10 = 15.8 = 16

Step-by-step explanation:

For Pythagoras we square route

= x^2 = 13^13 + (one of the closer squares for x elimination)

x= 169 + 81 169 + 100 169 + 49 169+64 169 + 121

x = 250 or 269 or 218 or 233 or 290

x= 5√10 or 15.8 or √269 269 or √218 2.8 or √233 or 2.33 ( or √290 = ( √48+2) or 2.9

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3 years ago

Last year Jacob made $2,300 at his summer job. This year he only made $1,771. What is the percent decrease?

MariettaO [177]

Answer:

23%

Step-by-step explanation:

$1,771 divided by $ 2,300 = 77%

100% - 77% = 23%

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3 years ago

Write the first five terms of the geometric sequence, given a1= -16 and r= -1/4

RUDIKE [14]

Answer: -16, 4, -1, 1/4,?

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Where n= the term.

So substituting the values for each term will give you the answer above. I don't know if it's tiredness or what but my fifth term gives me the same value as my fourth term.

3 0

3 years ago

In this triangle, a = 6 cm, b = 8 cm, and c = 10 cm.

tresset_1 [31]

Answer:

A) 24 cm²

Step-by-step explanation:

Area of a triangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

A = 24

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3 years ago

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svp [43]

The slope-point form of line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-9, 7) and (6, 2). Substitute:

$m=\dfrac{2-7}{6-(-9)}=\dfrac{-5}{6+9}=-\dfrac{5}{15}=-\dfrac{1}{3}\\\\y-7=-\dfrac{1}{3}(x-(-9))\\\\\boxed{y-7=-\dfrac{1}{3}(x+9)}$

The slope-intercept form of line:

$y=mx+b$ .

We have the slope m:

$y=-\dfrac{1}{3}x+b$

Pu the coordinates of the point (6, 2) to the equation:

$2=-\dfrac{1}{3}(6)+b$

$2=-2+b$ <em>add 2 to both sides</em>

$4=b\to b=4$

$\boxed{y=-\dfrac{1}{3}x+4}$

6 0

3 years ago