Question

Solve the compound inequality 6b < 24 or 4b + 12 > 4.

Answer 1

Yep :) The answer is A

Answer 2

Part 1:
$6b\ \textless \ 24$
$\frac{6b}{6} \ \textless \ \frac{24}{6}$
$b\ \textless \ 4$
Part 2:
$4b+12\ \textgreater \ 4$
$4b+12-12\ \textgreater \ 4-12$
$4b\ \textgreater \ -8$
$\frac{4b}{4}\ \textgreater \ \frac{-8}{4}$
$b\ \textgreater \ -2$
therefore the answer is...
$b\ \textless \ 4$ or $b\ \textgreater \ -2$