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Paul [167]
3 years ago
9

PLEASE HELP ME! What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equat

ion is y=−2x−6?
Enter your answer in the box.
Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

y=0.5x-2

Step-by-step explanation:

if it is perpendicular to the line y=-2x-6, then you know that its slope is the negative reciprocal of that line, and it has a different y intercept which you need to solve for using the point given. You solve by plugging in the x and y values from the point and plugging in the slope into the standard equation, and solving for b, the y intercept

y=0.5x+b

1=0.5(6)+b

1=3+b

-2=b


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<img src="https://tex.z-dn.net/?f=15%20%2B%205x%20%20%5C%5C%2014x%20-%206" id="TexFormula1" title="15 + 5x \\ 14x - 6" alt="15
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Reorder the terms:

6 + 14x = 15x

Solving

6 + 14x = 15x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15x' to each side of the equation.

6 + 14x + -15x = 15x + -15x

Combine like terms: 14x + -15x = -1x

6 + -1x = 15x + -15x

Combine like terms: 15x + -15x = 0

6 + -1x = 0

Add '-6' to each side of the equation.

6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 0 + -6

-1x = 0 + -6

Combine like terms: 0 + -6 = -6

-1x = -6

Divide each side by '-1'.

x = 6

Simplifying

x = 6


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